Answer to Question #3674 in Algebra for tami
A = A0 e^kt
Let's construct the system of equations
780 = 320 e 5k
780*3 = 780 ekt
5k = ln(780/320)
k = 0.178
3 = e 0.178 t
t = ln 3 / 0.178 = 6.165 hours
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This is actually 6.712 and if you calculate out 80/13 - you get 6.15....just depends on how picky your professor is.