# Answer to Question #3661 in Algebra for tami

Question #3661

Solve 2e

Moderate step by step would be great! Thanks!

^{2x}+ 19e^{x}-27=0.Moderate step by step would be great! Thanks!

Expert's answer

Denote e

2t

D = 19

t

t

e

^{x}as t, thus the equation is2t

^{2}+19t -27 = 0D = 19

^{2}+ 4*2*27 = 577t

_{1}= (-19 + √577)/4t

_{2}= (-19 - √577)/4 < 0 - doesnt's satisfy the conditions, as e^{x }>=0 at any x.e

^{x}= (-19 + √577)/4, x = ln(-19 + √577) - ln4Need a fast expert's response?

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