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Answer to Question #33573 in Algebra for Sageraza
Question #33573
b×b÷b+b×b-b=9
Expert's answer
b×b÷b+b×b-b=9
b×b÷b+b×b-b=b+b^2-b=b^2
So, b^2=9 whence b=3 or b=-3
Answer: 3,-3
b×b÷b+b×b-b=b+b^2-b=b^2
So, b^2=9 whence b=3 or b=-3
Answer: 3,-3
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