# Answer to Question #32394 in Algebra for Mark

Question #32394

Gold is 19 times as heavy as water, copper is 9 times as heavy as water. in what ratio should these be mixed to get an alloy 15 times as heavy as water?

Expert's answer

Suppose we have 1m^3 of water, 1m^3 of gold and 1m^3 of copper. Then we have for mass fractions 1 for water, 19 for gold and 9 for copper. We want to get 15 units of mass, so we need to get x m^3 of gold and 1-x m^3 of copper

19x+9(1-x)=15

19x+9-9x=15

10x=6

x=3/5

1-x=2/5

then we need to get 3 parts of gold and 2 parts of copper, so ratio is 3:2 gold to copper.

19x+9(1-x)=15

19x+9-9x=15

10x=6

x=3/5

1-x=2/5

then we need to get 3 parts of gold and 2 parts of copper, so ratio is 3:2 gold to copper.

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## Comments

Assignment Expert28.06.13, 12:07This is Algebra question.

Mark27.06.13, 17:19Please, what category does this question #32394 belong?

Assignment Expert27.06.13, 16:43<div>You're welcome. We are glad to be helpful.</div><div>If you really liked our service please press like-button beside answer field. Thank you!</div><div>

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Mark26.06.13, 17:42The answer is absolutely correct. I did it and got the ration to be same. Thanks.

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