64 517
Assignments Done
99,3%
Successfully Done
In September 2018

Answer to Question #32186 in Algebra for yashas

Question #32186
expand[3a-2b]^3
Expert's answer
In this taks we'll binom formula. We know formula for the third power of binom ( x - y )^3= x^3 -3x^2 * y + 3x*y^2 - y^3
In our case x=3a, y=2b, so we obtain
[3a-2b]^3 = ( 3a )^3 - 3*(3a)^2 * (2b) + 3*(3a)*(2b)^2 - ( 2b)^3= 27a^3 -3*9*a^2 * 2* b + 3*3*a*4*b^2 - 8*b^3=
=27a^3 -54*a^2 * b + 36*a*b^2 - 8*b^3

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be first!

Leave a comment

Ask Your question

Submit
Privacy policy Terms and Conditions