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Answer to Question #29210 in Algebra for judy hallak

Question #29210
3x-4y=6
5x-4y=2
Expert's answer
3x-4y=6
5x-4y=2
Let's subtract the first equation from the second:
2x=-4 whence x=-2
Now we can find y. Consider the first equation:
3*(-2)-4y=6
4y=-6-6=-12 whence y=-3
So the answer is (-2,-3)

We can verify obtained answer by substituting it into initial system:
3*(-2)-4*(-3)=6& <=> -6+12=6& <=> 6=6
5*(-2)-4*(-3)=2& <=> -10+12=2& <=> 2=2

We obtained right equalities hence our answer is correct because it turns the initial system into right equalities.

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