# Answer to Question #29210 in Algebra for judy hallak

Question #29210

3x-4y=6

5x-4y=2

5x-4y=2

Expert's answer

3x-4y=6

5x-4y=2

Let's subtract the first equation from the second:

2x=-4 whence x=-2

Now we can find y. Consider the first equation:

3*(-2)-4y=6

4y=-6-6=-12 whence y=-3

So the answer is (-2,-3)

We can verify obtained answer by substituting it into initial system:

3*(-2)-4*(-3)=6& <=> -6+12=6& <=> 6=6

5*(-2)-4*(-3)=2& <=> -10+12=2& <=> 2=2

We obtained right equalities hence our answer is correct because it turns the initial system into right equalities.

5x-4y=2

Let's subtract the first equation from the second:

2x=-4 whence x=-2

Now we can find y. Consider the first equation:

3*(-2)-4y=6

4y=-6-6=-12 whence y=-3

So the answer is (-2,-3)

We can verify obtained answer by substituting it into initial system:

3*(-2)-4*(-3)=6& <=> -6+12=6& <=> 6=6

5*(-2)-4*(-3)=2& <=> -10+12=2& <=> 2=2

We obtained right equalities hence our answer is correct because it turns the initial system into right equalities.

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