# Answer to Question #2840 in Algebra for Keyla

Question #2840

solving exponential equations with logarithms...

3^x=17

12^x=17

9^x=4.9

6^x= 0.51

18^2x=26

2^5x=34

3^x=17

12^x=17

9^x=4.9

6^x= 0.51

18^2x=26

2^5x=34

Expert's answer

x = log

x = log

x = log

x = log

x = ½ log

x = 1/5 log

_{3}17x = log

_{12}17x = log

_{9}4.9x = log

_{6}0.51x = ½ log

_{18}26x = 1/5 log

_{2}34Need a fast expert's response?

Submit orderand get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

## Comments

## Leave a comment