# Answer to Question #27092 in Algebra for Mildride

Question #27092

There were 80 runners to start a race. In the first half of the race, 2/5 of them dropped out. In the second half of the race, 3/8 of the remaining runners dropped out. How many runners finished the race?

Expert's answer

In the first half of the race, 2/5 of all runners droppedout.

Therefore it remains

80*(1-2/5) = 80*3/5 = 48 runners.

In the second half of the race, 3/8 of the remainingrunners dropped out, so it remains

48*(1-3/8) = 48*5/8 = 30 runners.

Thus, only 30 runners finished the race

Therefore it remains

80*(1-2/5) = 80*3/5 = 48 runners.

In the second half of the race, 3/8 of the remainingrunners dropped out, so it remains

48*(1-3/8) = 48*5/8 = 30 runners.

Thus, only 30 runners finished the race

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