# Answer to Question #26506 in Algebra for Taylor

Question #26506

In a recent year, the total sales at restaurant A were $450,000 more than at restaurant B. Total sales at the two stores were $600,000,000. What were the sales for the year at each store?

Expert's answer

Suppose, the total sales at restaurant A were $X. Then, the total sales at restaurant B were $(X-450,000).

Total sales at the two stores were $600,000,000:

X + (X-450,000) = 600,000,000

Solving this equation:

2X = 600,000,000 + 450,000

X = 600,450,000/2 = 300225000

Therefore, the total sales at restaurant A were $300,225,000.

For restaurant B we have:

300225000 - 450,000 = 299775000

Therefore, the total sales at restaurant B were $299,775,000.

Answer: the total sales at restaurant A were $300,225,000, at restaurant B - $299,775,000.

Total sales at the two stores were $600,000,000:

X + (X-450,000) = 600,000,000

Solving this equation:

2X = 600,000,000 + 450,000

X = 600,450,000/2 = 300225000

Therefore, the total sales at restaurant A were $300,225,000.

For restaurant B we have:

300225000 - 450,000 = 299775000

Therefore, the total sales at restaurant B were $299,775,000.

Answer: the total sales at restaurant A were $300,225,000, at restaurant B - $299,775,000.

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