Answer to Question #26165 in Algebra for fatma
(x-2)(x-1)(x+1)(2x-1)(3x^2 - 5x +3)=0
It's possible if one of the factors equals zero. Therefore we obtain the following equation: x-2=0 or x-1=0or x+1=0 or 2x-1=0 or 3x^2 - 5x +3 =0
So we have 4 real solutions and 2 complex.
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