# Answer to Question #25930 in Algebra for Kevin

Question #25930

A plumber makes 60 an hour if he already has saved 65 how Many hours must he work to save a least 275

Write,solve and check inequality

Write,solve and check inequality

Expert's answer

Suppose, he must work X hours to save a least 275:

60*X + 65 >= 275

60*X >= 275 - 65 = 210

X >= 210/60

X>= 3.5

For X = 3.5 he save:

60*3.5 + 65 = 210 + 65 = 275

Therefore

Answer: he must work (to save a least 275) 3.5 orlonger hours.

60*X + 65 >= 275

60*X >= 275 - 65 = 210

X >= 210/60

X>= 3.5

For X = 3.5 he save:

60*3.5 + 65 = 210 + 65 = 275

Therefore

Answer: he must work (to save a least 275) 3.5 orlonger hours.

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