Answer to Question #25605 in Algebra for raghav
2013-03-03T11:00:02-05:00
show that a number and its cube always leave the same remainder when divided by 6.
1
2013-03-12T10:51:01-0400
Any integer N can be represented in the form N = 6M + R, R<6, where M is a quotient and R is a remainder. Let's consider N³: N³ = (6M + R)³ = (6M)³ + 3(6M)²R + 3*6M*R² + R³. The first three terms of the sum are divisible by 6. Let's check what remainder does R³ leave when divided by 6: R = 1: 1³ (mod 6) = 1 = R; R = 2: 2³ (mod 6) = 8 (mod 6) = 2 = R; R = 3: 3³ (mod 6) = 27 (mod 6) = 3 = R; R = 4: 4³ (mod 6) = 64 (mod 6) = 4 = R; R = 5: 5³ (mod 6) = 125 (mod 6) = 5 = R. Therefore, a number and its cube always leave the same remainder when divided by 6.
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