# Answer to Question #24515 in Algebra for brittany

Question #24515

The formula for final velocity of an object starting from zero and undergoing constant acceleration is v=1/2at^2, what is the final velocity if a car is accelerating at 4 m/s^2 for 5 seconds

Expert's answer

This formula for distance:

s=1/2at^2

s - distance

a - acceleration

t - time

The formula for final velocity of an object starting from zero and undergoing constant acceleration is:

v=a*t

In our case:

a=4 m/s^2,

t= 5 sec,

Therefore:

v =a*t = 4m/s^2 * 5s = 20 m/sec = 20 m/sec &

s=1/2at^2

s - distance

a - acceleration

t - time

The formula for final velocity of an object starting from zero and undergoing constant acceleration is:

v=a*t

In our case:

a=4 m/s^2,

t= 5 sec,

Therefore:

v =a*t = 4m/s^2 * 5s = 20 m/sec = 20 m/sec &

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## Comments

Assignment Expert09.05.17, 19:48Dear visitor,

please use panel for submitting new questions

Kitten09.05.17, 17:19The formula for final velocity of an object starting from zero and undergoing constant acceleration is v=1/2at^2, what is the time it will take a car accelerating at 4 m/s^2 to reach 50m/s?

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