# Answer to Question #2436 in Algebra for shivam

Question #2436

If one of the zeroes of the polynomial 5x2 + 13x +k is reciprocal of the other, then

find the value of k.

find the value of k.

Expert's answer

5x

D = 169 - 20k

x

x

x

(-13 + √(169 - 20k))/10 = 10/ (-13 - √(169 - 20k))

100 = (-13 + √(169 - 20k))(-13 - √(169 - 20k)) = 169 - 169 + 20k = 20k

k = 10.

^{2}+ 13x + k = 0D = 169 - 20k

x

_{1}= (-13 + √(169 - 20k))/10x

_{2}= (-13 - √(169 - 20k))/10x

_{1 }= 1/x_{2}(-13 + √(169 - 20k))/10 = 10/ (-13 - √(169 - 20k))

100 = (-13 + √(169 - 20k))(-13 - √(169 - 20k)) = 169 - 169 + 20k = 20k

k = 10.

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