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Answer to Question #24008 in Algebra for raghav

Question #24008
• The value of m for which 2x+3y=11 , y=mx+3 , 2x-4y=-24 has common solution is?
Expert's answer
First, we find the solution for (1) 2x+3y=11
(2) 2x-4y=-24
(1) - (2):
2x-2x+3y-(-4y) = 35 => 7y=35
y=5
From the first:
2x+3*5=11 => 2x=-4
x=-2
Therefore y=mx+3 also has solution (-2, 5)
5=m*(-2) +3
m=-1
Answer: m=-1.

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