# Answer to Question #22666 in Algebra for clarkie

Question #22666

Completely factor the expression.

x^2 + 10x + 16

x^2 + 10x + 16

Expert's answer

x^2 + 10x + 16

Applying Vieta's theorem we get that x1x2=16, x1+x2=-10

Therefore x1=-8, x2=-2

So given expression is factored in the following way:

x^2 + 10x + 16=(x+2)(x+8)

Applying Vieta's theorem we get that x1x2=16, x1+x2=-10

Therefore x1=-8, x2=-2

So given expression is factored in the following way:

x^2 + 10x + 16=(x+2)(x+8)

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