Answer to Question #21736 in Algebra for arifa
[ (x-2)(x-8)] *[ (x-4)(x-6)]=9
so we have
x^2-10x+15=0 or x^2-10x+25=0
second x^2-10x+25=0 so (x-5)^2=0 x=5
x^2-10x+15=0 D=100-60=40 x1,2=(10+-2sqrt(10))/2=5+-sqrt(10)
we have three different roots
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thanks for such a nice help.