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Answer to Question #20659 in Algebra for miranda

Question #20659
Expert's answer
((4/(3r-1))-4)/((4/(3r-1))+4)=[ 4/(3r-1)-4(3r-1)/(3r-1)]/ [ 4/(3r-1) +4(3r-1)/(3r-1) ]= =[ (4-4(3r-1) )/(3r-1) ]/ [ (4+4*(3r-1)
)/(3r-1) ]= =[ (4-12r+4)/(3r-1) ]/ [ (4+12r-4)/(3r-1) ]= =[ (8-12r)/(3r-1)]/
[12r/(3r-1)]=(8-12r)/(12r)=8/(12r) -1=2/(3r) -1=(2-3r)/3r

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