# Answer to Question #19966 in Algebra for prince sharma

Question #19966

Proof that x^0=1

Expert's answer

We know, that:

(x^a)*(x^b) = x^(a+b)

1*x^b = x^b

So,

(x^0)*x^b = x^b => x^0=1

(x^a)*(x^b) = x^(a+b)

1*x^b = x^b

So,

(x^0)*x^b = x^b => x^0=1

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