# Answer to Question #1931 in Algebra for James

2x[sup]3[/sup] + 3x[sup]2[/sup] - 8x -12 = 0& (given that 2 is a root)

1
2011-03-16T10:02:23-0400

x_{1} = 2

(2x^{3} + 3x^{2} - 8x - 12)/(x-2) = 2x^{2} + 7x +6

2x^{2} + 7x +6 = 0

D = 49 - 48 = 1

x_{2} = -1.5

x_{3} = -2

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