Answer to Question #188554 in Algebra for angelo r reyes

Question

How many liters of a 95% muriatic acid solution and a 45% muriatic acid solution must be mixed to get 10 liters of 50% muriatic acid solution?

Answer 1

Let x be liters of a 95% muriatic acid solution.

And, given mixture mixed to get get 10 liters of 50% muriatic acid solution.

Therefore, according to the question

95x+45(10-x)=10*50

50x=50

x=1

Thus, 1 liters of a 95% muriatic acid solution and a 45% muriatic acid solution must be mixed to get 10 liters of 50% muriatic acid solution.