Question #18853

a kicker punts a football 3 feet above the ground with an initial velocity of 47 feet per second. write an equation that gives the height in feet of the football as a function of the time in seconds since it was punted

Expert's answer

The kicker punts the ball from 3 feet above the ground with an initialvelocity of 47 feet/s. Let the ball was kicked at angle a with the horizontal.

The initial velocity of the ball can be divide into the two components: ahorizontal component is 47*cos(a) ft/s and the vertical component is 47*sin(a)

ft/s.

An acceleration due to gravity of 32 ft/s^2 acts on the ball. Its heightafter t seconds is:

h(t) = 3 + 47*sin(a)*t - (1/2)*32*t^2.

The initial velocity of the ball can be divide into the two components: ahorizontal component is 47*cos(a) ft/s and the vertical component is 47*sin(a)

ft/s.

An acceleration due to gravity of 32 ft/s^2 acts on the ball. Its heightafter t seconds is:

h(t) = 3 + 47*sin(a)*t - (1/2)*32*t^2.

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