# Answer to Question #16069 in Algebra for rhobie

Question #16069

the length of a rectangle exceeds its width by three inches the area of the rectangle is seventy square inches

Expert's answer

Let's denote the length of the rectangle by L and it's width by W. Then we have the following system of equations:

L = W + 3, (1)

L*W = 70. (2)

Let's solve it.

(2): (W + 3)*W = 70 <==> W² + 3W - 70 = 0 ==> W = 7;

&

L = 7 + 3 = 10.

So, the length of the rectangle is 10 inches and the width is 7 inches.

L = W + 3, (1)

L*W = 70. (2)

Let's solve it.

(2): (W + 3)*W = 70 <==> W² + 3W - 70 = 0 ==> W = 7;

&

L = 7 + 3 = 10.

So, the length of the rectangle is 10 inches and the width is 7 inches.

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