Answer to Question #158232 in Algebra for Rizalyn Putong

Question

Construct a table of valued of the function using the interval of -5 to 5.

a. g(x)= x³+3x-5/x²

Answer 1

Solution

• Substitute value for x & get the corresponding $g(x)$ values.
• Interval for x values can be chosen as per the requirement. Here the interval is taken as unit 1

$\qquad\qquad \begin{aligned} g(-5)&=(-5)^3+3(-5)-\frac{5}{(-5)^2}\\ &=-125-15-0.2=-140.2\\ g(-4)&=(-4)^3+3(-4)-\frac{5}{(-4)^2}\\ &=-64-12-0.3125=-76.3125\\ g(-3)&=(-3)^3+3(-3)-\frac{5}{(-3)^2}\\ &=-27-9-0.5556=-36.5556\\ g(-2)&=(-2)^3+3(-2)-\frac{5}{(-2)^2}\\ &=-8-6-1.25=-15.25\\ g(-1)&=(-1)^3+3(-1)-\frac{5}{(-1)^2}\\ &=-1-3-5=-9\\ g(0)&=(0)^3+3(0)-\frac{5}{(-0)^2}\\ &=\infty\\ g(1)&=(1)^3+3(1)-\frac{5}{(1)^2}\\ &=1+3-5=-1\\ g(2)&=(2)^3+3(2)-\frac{5}{(2)^2}\\ &=8+6-1.25=12.75\\ g(3)&=(3)^3+3(3)-\frac{5}{(3)^2}\\ &=27+9-0.5556=35.4444\\ g(4)&=(4)^3+3(4)-\frac{5}{(4)^2}\\ &=64+12-0.3125=75.688\\ g(5)&=(5)^3+3(5)-\frac{5}{(5)^2}\\ &=125+15-0.2=139.8\\ \end{aligned}$

• Then the table is