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Answer to Question #14787 in Algebra for Taylor
Question #14787
THE PROBLEMS ARE SEPERATED BY |
1/3 x 1/4 | 13/16 x 1/3 | 5/6 x 7/8
1/3 x 1/4 | 13/16 x 1/3 | 5/6 x 7/8
Expert's answer
1/3 x 1/4=1/(3*4)=1/12
13/16 x 1/3=13/(16*3)=13/48
5/6 x 7/8=(5*7)/(6*8)=35/48
13/16 x 1/3=13/(16*3)=13/48
5/6 x 7/8=(5*7)/(6*8)=35/48
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