# Answer on Algebra Question for Taylor

Question #14787

THE PROBLEMS ARE SEPERATED BY |

1/3 x 1/4 | 13/16 x 1/3 | 5/6 x 7/8

1/3 x 1/4 | 13/16 x 1/3 | 5/6 x 7/8

Expert's answer

1/3 x 1/4=1/(3*4)=1/12

13/16 x 1/3=13/(16*3)=13/48

5/6 x 7/8=(5*7)/(6*8)=35/48

13/16 x 1/3=13/(16*3)=13/48

5/6 x 7/8=(5*7)/(6*8)=35/48

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