# Answer to Question #14787 in Algebra for Taylor

Question #14787

THE PROBLEMS ARE SEPERATED BY |

1/3 x 1/4 | 13/16 x 1/3 | 5/6 x 7/8

1/3 x 1/4 | 13/16 x 1/3 | 5/6 x 7/8

Expert's answer

1/3 x 1/4=1/(3*4)=1/12

13/16 x 1/3=13/(16*3)=13/48

5/6 x 7/8=(5*7)/(6*8)=35/48

13/16 x 1/3=13/(16*3)=13/48

5/6 x 7/8=(5*7)/(6*8)=35/48

Need a fast expert's response?

Submit orderand get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

## Comments

## Leave a comment