# Answer on Algebra Question for Jaclyn

Question #14469

Make the variable in the bracket the subject of the given formula:

1. px-q=rx+s {x}

2. s = a/(1-r) {r}

3. A = 1/2(a+b)h {a}

1. px-q=rx+s {x}

2. s = a/(1-r) {r}

3. A = 1/2(a+b)h {a}

Expert's answer

1. px-q=rx+s {x}

px-rx=s+q

x(p-r)=s+q

x=(s+q)/(p-r)

2. s = a/(1-r) {r}

s(1-r)=a

s-sr=a

sr=s-a

r=(s-a)/s

3. A = 1/2{(a+b)h} {a}

2A=ah+bh

ah=2A-bh

a=(2A-bh)/h

px-rx=s+q

x(p-r)=s+q

x=(s+q)/(p-r)

2. s = a/(1-r) {r}

s(1-r)=a

s-sr=a

sr=s-a

r=(s-a)/s

3. A = 1/2{(a+b)h} {a}

2A=ah+bh

ah=2A-bh

a=(2A-bh)/h

Need a fast expert's response?

Submit orderand get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

## Comments

Assignment Expert07.09.2012 11:56ab/{a+b} =1

ab=a+b

ab-a=b

a(b-1)=b

a=b/(b-1)

Jaclyn07.09.2012 11:52Then ab/a+b = 1 {a}

Assignment Expert07.09.2012 11:49Ok, then

A = 1/{2(a+b)h} whence

2(a+b)h=1/A

a+b=1/{2hA}

a=1/{2hA}-b

Jaclyn07.09.2012 11:452{(a+b)h} is a denominator

Assignment Expert07.09.2012 11:43A = 1/2{(a+b)h}=1/2*{(a+b)h}

so 2*A={(a+b)h}

Or you've meant that 2{(a+b)h} is a denominator?

Jaclyn07.09.2012 11:363. A = 1/2{(a+b)h} {a}

2A=ah+bh

ah=2A-bh

a=(2A-bh)/h

How did you get 2A?

## Leave a comment