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Answer to Question #14469 in Algebra for Jaclyn

Question #14469
Make the variable in the bracket the subject of the given formula:
1. px-q=rx+s {x}
2. s = a/(1-r) {r}
3. A = 1/2(a+b)h {a}
Expert's answer
1. px-q=rx+s {x}
px-rx=s+q
x(p-r)=s+q
x=(s+q)/(p-r)

2. s = a/(1-r) {r}
s(1-r)=a
s-sr=a
sr=s-a
r=(s-a)/s

3. A = 1/2{(a+b)h} {a}
2A=ah+bh
ah=2A-bh
a=(2A-bh)/h

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Comments

Assignment Expert
07.09.12, 18:56

ab/{a+b} =1
ab=a+b
ab-a=b
a(b-1)=b
a=b/(b-1)

Jaclyn
07.09.12, 18:52

Then ab/a+b = 1 {a}

Assignment Expert
07.09.12, 18:49

Ok, then
A = 1/{2(a+b)h} whence
2(a+b)h=1/A
a+b=1/{2hA}
a=1/{2hA}-b

Jaclyn
07.09.12, 18:45

2{(a+b)h} is a denominator

Assignment Expert
07.09.12, 18:43

A = 1/2{(a+b)h}=1/2*{(a+b)h}
so 2*A={(a+b)h}
Or you've meant that 2{(a+b)h} is a denominator?

Jaclyn
07.09.12, 18:36

3. A = 1/2{(a+b)h} {a}
2A=ah+bh
ah=2A-bh
a=(2A-bh)/h
How did you get 2A?

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