Answer to Question #14412 in Algebra for john
The actual voltage is 120⋅2√⋅cos(2π⋅60⋅t) Volts. If we apply this voltage across a resistor of resistance 110.0Ω the resistor will dissipate a time-varying power. What is the peak power (in Watts) dissipated by the resistor?
What is the average power (in Watts) dissipated by the resistor? (Hint: you compute the average power by integrating the instantaneous power over one cycle of the waveform.)
What would be the power (in Watts) dissipated by the resistor if the voltage was a constant value of 120V?
If a time-varying, AC voltage dissipates the same power in a resistor as a constant voltage would dissipate, we say that the time-varying voltage has a root-mean-square (RMS) value that is equal to the constant voltage.
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