Question #14412

The plot shows 1/10 second of the voltage waveform of a 120V 60Hz AC (Alternating Current) power circuit, like that delivered to residences in the United States.

The actual voltage is 120⋅2√⋅cos(2π⋅60⋅t) Volts. If we apply this voltage across a resistor of resistance 110.0Ω the resistor will dissipate a time-varying power. What is the peak power (in Watts) dissipated by the resistor?

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What is the average power (in Watts) dissipated by the resistor? (Hint: you compute the average power by integrating the instantaneous power over one cycle of the waveform.)

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What would be the power (in Watts) dissipated by the resistor if the voltage was a constant value of 120V?

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If a time-varying, AC voltage dissipates the same power in a resistor as a constant voltage would dissipate, we say that the time-varying voltage has a root-mean-square (RMS) value that is equal to the constant voltage.

The actual voltage is 120⋅2√⋅cos(2π⋅60⋅t) Volts. If we apply this voltage across a resistor of resistance 110.0Ω the resistor will dissipate a time-varying power. What is the peak power (in Watts) dissipated by the resistor?

unanswered

What is the average power (in Watts) dissipated by the resistor? (Hint: you compute the average power by integrating the instantaneous power over one cycle of the waveform.)

unanswered

What would be the power (in Watts) dissipated by the resistor if the voltage was a constant value of 120V?

unanswered

If a time-varying, AC voltage dissipates the same power in a resistor as a constant voltage would dissipate, we say that the time-varying voltage has a root-mean-square (RMS) value that is equal to the constant voltage.

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