Answer to Question #133082 in Algebra for Peters Nathan

Question

Prove the inequality:
|cos(x)|≥1-sin²(x) holds true for all x∈R

Answer 1

From given, we have,

| cos(x)| ≥ 1 − sin² (x)

upon removing the mod, we get,

cos x ≤ - (1 - sin²x) and cos x ≥ (1 - sin²x)

Now consider,

cos x ≤ - (1 - sin²x)

cos x ≤ - 1 + sin²x

cos x - sin²x + 1 ≤ 0

cos x - (1 - cos²x) + 1 ≤ 0

cos x + cos²x ≤ 0

-1 ≤ cos x ≤ 0

True for all x ∈ R and π/2+2πn≤x≤3π/2+2πn .......(1)

Now consider,

cos x ≥ (1 - sin²x)

cos x ≥ 1 - sin²x

cos x + sin²x - 1 ≥ 0

cos x + (1 - cos²x) - 1 ≥ 0

cos x - cos²x + 1 ≥ 1

0 ≤ cos x ≤ 1

True for all x ∈ R and -π/2+2πn ≤ x ≤ π/2+2πn .......(2)

combining equations (1) and (2), we get,

True for all x ∈ R and -π/2+2πn ≤ x ≤ 3π/2+2πn