Answer to Question #125251 in Algebra for EMMANUEL

Question #125251

Simplify X^p+(1/2)q × Y^2p-q ÷ (XY^2)^p × √X^q

Expert's answer

"\\dfrac{x^{p+\\frac{1}{2}q} \\cdot y^{(2p-q)}}{(x\\cdot y^2)^p \\cdot \\sqrt{x}^q} =\n\\dfrac{x^p\\cdot x^{\\frac{1}{2}q} \\cdot y^{2p}\\cdot y^{-q}}{x^p\\cdot y^{2p} \\cdot x^{\\frac{1}{2}q}} =\ny^{-q}"

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