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Answer to Question #11928 in Algebra for Elise Ruby

Question #11928
Forty ounces of a 35% gold alloy are mixed with 62 ounces of a 20% alloy. Find the concentration of the resulting gold alloy.
Expert's answer
So in forty ounces there are 40*0,35 ounces of pure gold. In 62 ounces there are 62*0,2& ounces of pure gold. So resulting concentration is (40*0,35+62*0,2)/(40+62)*100%=(14+12,4)/102*100%=25,9%

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