# Answer to Question #11452 in Algebra for Allie

Question #11452

Subject: Exponential and Logarithmic functions
Question:
The radioactive isotope XYZ-aaa(aaaXYZ) has a half-life of 6 hours. If 15 milligrams are used, how much will be present after 29 hours? Round the answer to three decimal places.

Expert's answer

We'll use the next formula:

N(t) = N0/2^(t/T),

where N0 is initial quantity of a radioactive isotope, T - half-life period. So, there remains

N(29) = 15/2^(29/6) ≈ 0.526 milligrams

of radioactive isotope after 29 hours.

N(t) = N0/2^(t/T),

where N0 is initial quantity of a radioactive isotope, T - half-life period. So, there remains

N(29) = 15/2^(29/6) ≈ 0.526 milligrams

of radioactive isotope after 29 hours.

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