# Answer to Question #11045 in Algebra for n lakshmi

factorize

2x^2+2(squareroot)6xy + 3y^2

1
2012-06-19T10:39:38-0400

we use (a+b)^2=a^2+2ab+b^2

2x^2+2(squareroot)6xy +

3y^2=(sqrt(2)*x)^2+2*sqrt(2)*x*sqrt(3)*y+(sqrt(3)*y)^2=use formula=(

sqrt(2)*x+sqrt(3)*y )^2

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