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Answer to Question #11044 in Algebra for n lakshmi
Question #11044
factorize
4a^2 -4(squareroot)3 a+3
4a^2 -4(squareroot)3 a+3
Expert's answer
we use (x-y)^2=x^2-2xy+y^2
4a^2
-4*sqrt(3)*a+3=(2a)^2-2*sqrt(3)*2a+(sqrt(3))^2=(2a-sqrt(3))^2
4a^2
-4*sqrt(3)*a+3=(2a)^2-2*sqrt(3)*2a+(sqrt(3))^2=(2a-sqrt(3))^2
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#340153 on Dec 2023
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