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Answer to Question #10812 in Algebra for Melvin Henriksen
Question #10812
Please factorize the polynomial (x+y)^2+3xy^2-x^3+xy-y^3+3x^2y
Expert's answer
If we take g1=x+y and g2=xy then our expression can be simplified as
(g1)^3+3(g1)(g2)+g2-(g1)^3+3(g1)(g2)=(6g1+1)g2=
=(6x+6y+1)xy
(g1)^3+3(g1)(g2)+g2-(g1)^3+3(g1)(g2)=(6g1+1)g2=
=(6x+6y+1)xy
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#340153 on Dec 2023
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