52 868
Assignments Done
97,9%
Successfully Done
In October 2017
Your physics homework can be a real challenge, and the due date can be really close — feel free to use our assistance and get the desired result.
Be sure that math assignments completed by our experts will be error-free and done according to your instructions specified in the submitted order form.
Our experts will gladly share their knowledge and help you with programming homework. Keep up with the world’s newest programming trends.

Answer on Algebra Question for nksprasad

Question #10686
factorize a^3+b^3-c^3+3abc
Expert's answer
factorize a³+b³-c³+3abc

(a + b + c)(a² + b² + c² + x)

a³ + ab² + ac² + ax
ba² + b³ + c²b + bx
ca² + cb² + c³ + cx

a³, b³, c³ are all valid
ab² + ac² + ba² + c²b + ca² + cb² + ax + bx + cx are not.

They need to cancel out and any variable multiplied on the other side would give you the square of that variable

- ab - bc - ac

This really does check out:

= a^3 + ab² + c²a +a( - ab - bc - ac) +
+ ba² + b³ + bc² + b( - ab - bc - ac) +
+ ca² + cb² + c³ + c(- ab - bc - ac) =
= a³ + b³ + c³ - 3abc

(a + b + c)(a² + b² + c² - ab - bc - ac) =
= a³ + b²a + c²a - a²b - abc - a²c +
+ ba² + b³ + c²b - ab² - b²c - abc +
+ ca² + cb² + c³ - acb -c²b - ac² =
= a³ + b³ + c³ - 3abc.

So,

a³+b³-c³+3abc = (a + b + c)(a² + b² + c² - ab - bc - ac).

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be first!

Leave a comment

Ask Your question