# Answer to Question #7386 in Abstract Algebra for yuran langa

Question #7386

A coin was tossed 10 times and the outcomes noted as H,T,H,H,T,T,T,T,H,T where H is Head and T is Tail. Find the estimated probability of a tail.

Expert's answer

We'll use classical definition of probability

Due to it probability of event A P(A)={number of favourable events}/{total number of events}=n/N

In opur case event A-getting a tail.

N=10

n=6 (number of letters T in the list)

Therefore p(A)=6/10=3/5

Due to it probability of event A P(A)={number of favourable events}/{total number of events}=n/N

In opur case event A-getting a tail.

N=10

n=6 (number of letters T in the list)

Therefore p(A)=6/10=3/5

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