# Answer to Question #25476 in Abstract Algebra for irfan

Question #25476

√64-√p+√q=9 find p+q

Expert's answer

√64-√p+√q=9 find p+q

-√p+√q=9-8

-√p+√q=1

Moreover p and q are natural numbers.

After Squaring we have: p+q-2*sqrt(pq)=1

Then q=9, p=4.

-√p+√q=9-8

-√p+√q=1

Moreover p and q are natural numbers.

After Squaring we have: p+q-2*sqrt(pq)=1

Then q=9, p=4.

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## Comments

Assignment Expert06.03.13, 12:29Dear visitor

In this expression p+q-sqrt (pq) the factor 2 is missing, actually it should be p+q-2*sqrt (pq).&

Thanks for correcting us!

irfan06.03.13, 11:28i don't get it... because when we subst 9 and 4 to p+q-sqrt (pq) is not wqual to 1

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