Answer to Question #24149 in Abstract Algebra for Xane
2013-02-10T11:34:36-05:00
How to do this sum: 2 over x-y plus 1 over x( to the power of two) - y( to the power of two)
1
2013-02-15T04:14:46-0500
We have the following statement: A = 2/(x-y) + 1/(x²-y²). First, let's reduce this statement to the common denominator. The common denominator is (x²-y²), as (x²-y²) = (x+y)(x-y). Therefore A = 2/(x-y) + 1/(x²-y²) = = 2(x+y)/((x-y)(x+y)) + 1/(x²-y²) = = 2(x+y)/(x²-y²) + 1/(x²-y²) = = (2(x+y) + 1)/(x²-y²) = = (2x+2y+1)/(x²-y²). So, 2/(x-y) + 1/(x²-y²) = (2x+2y+1)/(x²-y²).
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