For finite abelian groups G and H, show that RG ∼ RH as R-algebras iff |G| = |H| and |G/G2| = |H/H2|.
1
Expert's answer
2013-02-05T10:39:32-0500
Since G is abelian, Wedderburn’s Theoremgives: RG ∼ R×· ··×R × C×· · ·×C.Suppose there are s factors ofR, and t factors of C, so that |G| = s + 2t. Thenumber s is the number of 1-dimensional real representations of G.This is the number of group homomorphisms from G to {±1} ⊆R*, so s = |G/G2|. Therefore, the isomorphism typeof RG (as an R-algebra) is uniquely determined by |G| and |G/G2|.The conclusion follows immediately from this.
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
Finding a professional expert in "partial differential equations" in the advanced level is difficult.
You can find this expert in "Assignmentexpert.com" with confidence.
Exceptional experts! I appreciate your help. God bless you!
Comments
Leave a comment