Answer to Question #16973 in Abstract Algebra for laura
a frog lies at the bottom of a well whose depth is 30m. It starts to climb, rising up 2/5 every day and falling back 1/5 every night. How long will it take him to climb out of the well?
As the frog rises 2/5 every day and falling back 1/5 every night, then its 24-hour rising is
2/5 - 1/5 = 1/5 m.
So, it will take
N = 30/ (1/5) = 30*5 = 150 days
to climb out.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!