# Answer to Question #16973 in Abstract Algebra for laura

Question #16973

a frog lies at the bottom of a well whose depth is 30m. It starts to climb, rising up 2/5 every day and falling back 1/5 every night. How long will it take him to climb out of the well?

Expert's answer

As the frog rises 2/5 every day and falling back 1/5 every night, then its 24-hour rising is

2/5 - 1/5 = 1/5 m.

So, it will take

N = 30/ (1/5) = 30*5 = 150 days

to climb out.

2/5 - 1/5 = 1/5 m.

So, it will take

N = 30/ (1/5) = 30*5 = 150 days

to climb out.

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