# Answer to Question #14993 in Abstract Algebra for aunjelic

Question #14993

1. 4c-3=63 ?

2.3p+85=2p-10

3.6h+7=7h-5

4.14k-1=

5.7e-4=2e+13

2.3p+85=2p-10

3.6h+7=7h-5

4.14k-1=

5.7e-4=2e+13

Expert's answer

1. 4c-3=63

4с=63+3=66

с=66/4=33/2

2.3p+85=2p-10

3p-2p=-85-10

p=-95

3.6h+7=7h-5

7-5=7h-6h

h=2

4с=63+3=66

с=66/4=33/2

2.3p+85=2p-10

3p-2p=-85-10

p=-95

3.6h+7=7h-5

7-5=7h-6h

h=2

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