Answer to Question #1399 in Abstract Algebra for mohsin
Let's denote the width as x, thus the area of the whole part whould be
S2 = (80 + 2x)(60+ 2x) = 4800 + 280x + 4x2
The area of the outer path is S2-S1 = 4800 + 280x + 4x2 - 4800 = 4x2 + 280x = 1500
Solve the following equation:
4x2 + 280x -1500 = 0
x2 + 70x - 375 = 0
D = 352 + 375 = 1600
x1 = -35 + 40 = 5
x2 = -35 -40 = -75 - out of sence in our case.
Answer: the width is 5m.
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