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Answer to Question #13822 in Abstract Algebra for Charissa

Question #13822
Task
1.) 32^ 2/5
2.)125 2/3
3)8 2/3
4.)16 2/3
5.)4 3/2
6.)32 2/5+64 2/3
Expert's answer
1.) 32^ 2/5=(2^5)^2/5=2^2=4
& 2.)125^2/3=(5^3)^2/3=25
& 6.)32^2/5+64^2/3=(2^5)^2/5+(2^6)^2/3=4+16=20
and so on

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