Answer to Question #35911 in Other Engineering for ryan
Question #35911
A car of mass 1100 kg drives with a velocity such that it has a kinetic energy of 400 kJ. Find its speed. If the car is raised with a crane, how high should it be lifted in the standard gravitational field to have a potential energy that equals the kinetic energy?
Expert's answer
E = mv^2/2
hence we can find velocity v = sqrt(2E/m) = sqrt(2*400*10^3 J/1100) = 27 m/s
When potential energy equals kinetic
mgh=mv^2/2=400kJ
The height is
h = mv^2/(2m*g) = 400kJ/(1100kg*9.8 m/s^2) = 37.1 m
hence we can find velocity v = sqrt(2E/m) = sqrt(2*400*10^3 J/1100) = 27 m/s
When potential energy equals kinetic
mgh=mv^2/2=400kJ
The height is
h = mv^2/(2m*g) = 400kJ/(1100kg*9.8 m/s^2) = 37.1 m
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