Question #195357

A negative charge -q is fixed to one corner of a rectangle, as shown in figure 3. What positive charge must be fixed to corner A and what positive charge must be fixed to corner B, so the total electric field at the remaining corner is zero? Express your answer in terms of q.

Expert's answer

"k\\frac{q}{2a^2}-k\\frac{q'}{2a^2}-k\\frac{q'}{2a^2}=0\\\\q'=0.5q"

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