# Answer to Question #13021 in Other Engineering for Kim Rogers

Question #13021

2500 kg pickup accelerates from 0 to 100 km/hr in 10 s along level road. What would be corresponding time when pulling 500 kg trailer? Assume constant acceleration and neglect all retarding forces.

Expert's answer

When pickup accelerates from 0 to 100 km/h (=100*1000/3600 m/s = 27.(7) m/s) in 10 s the acceleration of a pickup is

a1 = 27.(7)m/s / 10s = 2.(7) m/s².

The corresponding force is

F = m*a1 = 2500kg * 2.(7) m/s² = 6944.(4) N.

The acceleration when pulling 500 kg trailer will be

a2 = 6944.(4)N/(2500kg + 500kg) = 2.3(148) m/s².

So, the pickup pulling 500 kg trailer will accelerate from 0 to 100 km/h in

t = 27.(7)m/s / 2.3(148)m/s² = 12 s.

a1 = 27.(7)m/s / 10s = 2.(7) m/s².

The corresponding force is

F = m*a1 = 2500kg * 2.(7) m/s² = 6944.(4) N.

The acceleration when pulling 500 kg trailer will be

a2 = 6944.(4)N/(2500kg + 500kg) = 2.3(148) m/s².

So, the pickup pulling 500 kg trailer will accelerate from 0 to 100 km/h in

t = 27.(7)m/s / 2.3(148)m/s² = 12 s.

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