Question #83007

The food compartment of a refrigerator, is maintained at 4°C by
removing heat from it at a rate of 360 kJ/min. If the required power input
to the refrigerator is 2 kW, determine (a) the coefficient of performance of
the refrigerator and (b) the rate of heat rejection to the room that houses
the refrigerator.

Expert's answer

Let us convert the cooling load (Q) of the refrigerator to kW:

Q=360 kJ/min=6 kW.

The coefficient of performance (COP) of the refrigerator is given by the ratio of the cooling load and input power (W). Thus:

COP=Q/W=6/2=3.

The rate of heat rejection (H) to the room is equal to the sum of the refrigerator cooling load and input power:

H=Q+W=6+2=8 kW.

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