Answer to Question #246489 in Mechanical Engineering for Asas

Question

A boiler consumes 16,800 pounds of feul/hr when producing 210,000

lb of steam per hour at 620 psia and 800 deg F from feed water at

650 psia and 800F from feed water at 650 psia and 300F. The

heating value of fuel is 18,500 Btu/lb and the furnace volume is 1250

ft. Calculate: a) boiler capacity in mb/hr ; b) factor of evaporation ; c) equivalent evaporation ; d) furnace heat-release rate in Btu/hr-ft^3 ; e) boiler efficiency

Answer 1

fuel consumption rate = 16,800 lb/hr

mass of steam produced = 210,000 lb/hr

conditions of steam;

pressure = 620 psia

temperature = 800 °F

conditions of water initally;

pressure = 650 psia

temperature = 300°F

heating value of fuel = 18,500 Btu/lb

furnace volume = 1250ft³

boiler capacity = heating value of fuel × fuel consumption rate

boiler capacity = $18500 ×16800$ = $310800000 \textsf{ Btu/hr}$ = $310.8 \textsf{ mb/hr}$