In a non flow process there is heat transfer loss of 1055kJ and internal energy increase of 210kJ determine the work transfer and state whether the process is expansion or compression
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Expert's answer
2021-10-05T14:33:01-0400
Q=−1055kJ∆U=210kJW=?
∆U=Q−W210=−1055−WW=1265kJ
Since work done is positive, there is an increase in volume.
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