Answer to Question #240224 in Mechanical Engineering for Blaze

Question #240224
2.4 A force F is applied at point A of the block with edge lengths of a, b, c Determine (1) the projections of F on the x, y and z axes; (2) the moments of F about x, y and z axes; (3) the moment of F about OB axis.
1
Expert's answer
2021-09-22T00:22:41-0400



(1)


"F_x=-|\\vec F|\\sin \\beta\\cos \\alpha"

"F_y=-|\\vec F|\\cos \\beta\\cos \\alpha"

"F_z=|\\vec F|\\sin \\alpha"

(2)


"\\vec F=(-|\\vec F|\\sin \\beta\\sin \\alpha, -|\\vec F|\\sin \\beta\\cos \\alpha, |\\vec F|\\cos \\beta)"

"\\vec r=(a, b, c)"

"\\vec M_O=\\vec r \\times\\vec F"

"=\\begin{vmatrix}\n \\vec i & \\vec j & \\vec k \\\\\na & b & c\\\\\n-|\\vec F|\\sin \\beta\\cos \\alpha & -|\\vec F|\\cos \\beta\\cos \\alpha & |\\vec F|\\sin \\alpha\\\\\n\\end{vmatrix}"

"=( |\\vec F|b\\sin \\alpha+|\\vec F|c\\cos \\beta\\cos \\alpha)\\vec i"

"+(- |\\vec F|a\\sin \\alpha-|\\vec F|c\\sin \\beta\\cos \\alpha)\\vec j"

"+(- |\\vec F|a\\cos \\alpha\\cos \\beta+|\\vec F|b\\sin \\beta\\cos \\alpha)\\vec k"

"M_x=\\vec i\\cdot(\\vec r\\times\\vec F)="

"= |\\vec F|b\\sin \\alpha+|\\vec F|c\\cos \\beta\\cos \\alpha"

"M_y=\\vec j\\cdot(\\vec r\\times\\vec F)="

"=- |\\vec F|a\\sin \\alpha-|\\vec F|c\\sin \\beta\\cos \\alpha"

"M_z=\\vec k\\cdot(\\vec r\\times\\vec F)="

"- |\\vec F|a\\cos \\alpha\\cos \\beta+|\\vec F|b\\sin \\beta\\cos \\alpha"

(3)


"\\overrightarrow{OB}=(a, 0, c))"

"\\vec u=(\\dfrac{a}{\\sqrt{a^2+b^2}}, 0, \\dfrac{c}{\\sqrt{a^2+c^2}})"

"M_{OB}=\\vec u\\cdot(\\vec r\\times\\vec F)="

"=\\dfrac{ |\\vec F|ab\\sin \\alpha+|\\vec F|ac\\cos \\beta\\cos \\alpha}{\\sqrt{a^2+b^2}}"

"+\\dfrac{- |\\vec F|ac\\cos \\alpha\\cos \\beta+|\\vec F|bc\\sin \\beta\\cos \\alpha}{\\sqrt{a^2+b^2}}"

"=\\dfrac{ |\\vec F|ab\\sin \\alpha+|\\vec F|bc\\sin \\beta\\cos \\alpha}{\\sqrt{a^2+b^2}}"


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Comments

Blaze
23.09.21, 09:12

Thank you so much!

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